Boiling ponds and pools on Mars?

The pressure on the surface of Mars according to https://en.wikipedia.org/wiki/Atmosphere_of_Mars is

The atmospheric pressure on the Martian surface averages 600 pascals (0.087 psi; 6.0 mbar), about 0.6% of Earth's mean sea level pressure of 101.3 kilopascals (14.69 psi; 1.013 bar).

This chart http://www.engineersedge.com/h2o_boil_pressure.htm seems to indicate that the 77F water would be above its boiling point by more than 75F (the granularity of the chart does not give more info).

This would result in a (perhaps explosive) boiling of the pool until it had released enough energy to be below its boiling point in the 6F to -24F range. At this point the remaining water may freeze and sublimate in the future.

BUT, according to https://en.wikipedia.org/wiki/Mars the surface of Mars is between -226F and 95F, so depending on conditions the pool may never cool below its boiling point, and all of it simply evaporates.

Edit @Dean MacGregor correctly points out that at 600Pa water will never be a stable liquid, so the final result (after 'explosive' boiling) will eventually be that all the water evaporates, or a portion boils off, allowing the remainder to cool to ice, which may or may not sublimate. All depending largely on the temperature of this particular part of Mars

Here's a phase diagram of water.

If you find Mars's atmosphere of 600Pa on the Y-axis and track right you'll see that H20 can't be water on Mars. It can only be ice or vapor.

In your example where you have a dome of Earth like atmosphere protecting your Martian pool that blows away somehow then you'll either have a skating rink or an empty hole but no water. Going by the average Martian temperature you'd have a skating rink but once the temperature exceeds the sublimation point all your H2O would turn to vapor and that'd be the end of it.

Edit:

The other answer asserts that it would first boil and perhaps there'd be some H20 left as ice after some of it boiled off. I suppose this depends on the exact circumstances of losing the dome. The way OP asks the question, it seems that first heat is lost and then the dome goes away. If the water has already cooled to below the sublimation point before the pressure drop occurs then there's no need for it to boil. If everything is working fine and then the dome flies away while the ambient temperature is above boiling temperature then clearly it would boil off. However, if the ambient temperature is below sublimation when the dome is lost I don't think it is clear that the water would boil rather than freeze. The very act of decompressing would cool the water so we can't simply say that the pressure can drop faster than the water cools because the pressure dropping speeds the cooling.