Dodecahedron

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A general dodecahedron is a polyhedron having 12 faces. Examples include the decagonal prism, elongated square dipyramid (Johnson solid J_(15)), hexagonal dipyramid, metabidiminished icosahedron (J_(62)), pentagonal antiprism, pentagonal cupola (J_5), (regular) dodecahedron, rhombic dodecahedron, snub disphenoid (J_(84)), triakis tetrahedron, and undecagonal pyramid. Crystals of pyrite (FeS_2) resemble slightly distorted dodecahedra (Steinhaus 1999, pp. 207-208), and sphalerite (ZnS) crystals are irregular dodecahedra bounded by congruent deltoids (Steinhaus 1999, pp. 207 and 209). The hexagonal scalenohedron is another irregular dodecahedron.

DodecahedronDodecahedronNetDodecahedronNet
DodecahedronProj1DodecahedronProj2DodecahedronProj3
DodecahedronProj4DodecahedronProj5

polyhdron net The regular dodecahedron, often simply called "the dodecahedron," is the Platonic solid P_2 composed of 20 polyhedron vertices, 30 polyhedron edges, and 12 pentagonal faces, 12{5}. It is also uniform polyhedron U_(23) and Wenninger model W_5. It is given by the Schläfli symbol {5,3} and the Wythoff symbol 3|25.

There are 43380 distinct nets for the dodecahedron, the same number as for the icosahedron (Bouzette and Vandamme, Hippenmeyer 1979, Buekenhout and Parker 1998). Questions of polyhedron coloring of the dodecahedron can be addressed using the Pólya enumeration theorem.

Origami dodecahedron

The image above shows an origami dodecahedron constructed using six dodecahedron units, each consisting of a single sheet of paper (Kasahara and Takahama 1987, pp. 86-87).

A dodecahedron appears as part of the staircase being ascending by alligator-like lizards in Escher's 1943 lithograph "Reptiles" (Bool et al. 1982, p. 284; Forty 2003, Plate 32). Two dodecahedra also appear as polyhedral "stars" in M. C. Escher's 1948 wood engraving "Stars" (Forty 2003, Plate 43). The IPV pod that transports Ellie Arroway (Jodi Foster) through a network of wormholes in the 1997 film Contact was enclosed in a dodecahedral framework.

Charles Perry's Eclipse sculpture

A 40-foot high sculpture (Nath 1999) known as Eclipse is displayed in the Hyatt Regency Hotel in San Francisco. It was constructed by Charles Perry, and is composed of 1440 pieces of anodized aluminum tubes and assembled over a period of four months (Kraeuter 1999). The layered sculpture begins with a regular dodecahedron, but each face then rotates outward. At the midpoint of the rotation, it forms an icosidodecahedron. Then, as the 12 pentagons continue to rotate outward, it forms a small rhombicosidodecahedron.

Dodecahedra were known to the Greeks, and 90 models of dodecahedra with knobbed vertices have been found in a number of archaeological excavations in Europe dating from the Gallo-Roman period in locations ranging from military camps to public bath houses to treasure chests (Schuur).

DodecahedralGraph

The dodecahedron has the icosahedral group I_h of symmetries. The connectivity of the vertices is given by the dodecahedral graph. There are three dodecahedron stellations.

DodecahedronAndDual
dodinicoicoindod

The dual polyhedron of a dodecahedron with unit edge lengths is an icosahedron with edge lengths phi, where phi is the golden ratio. As a result, the centers of the faces of an icosahedron form a dodecahedron, and vice versa (Steinhaus 1999, pp. 199-201).

DodecahedronHexagon1DodecahedronHexagon2
DodecahedronDecagon1DodecahedronDecagon2

A plane perpendicular to a C_3 axis of a dodecahedron cuts the solid in a regular hexagonal cross section (Holden 1991, p. 27). A plane perpendicular to a C_5 axis of a dodecahedron cuts the solid in a regular decagonal cross section (Holden 1991, p. 24).

DodecahedronCubeDodecahedronGolden

A cube can be constructed from the dodecahedron's vertices taken eight at a time (above left figure; Steinhaus 1999, pp. 198-199; Wells 1991). Five such cubes can be constructed, forming the cube 5-compound. In addition, joining the centers of the faces gives three mutually perpendicular golden rectangles (right figure; Wells 1991).

RhombicTriacontDodec

The short diagonals of the faces of the rhombic triacontahedron give the edges of a dodecahedron (Steinhaus 1999, pp. 209-210).

The following table gives polyhedra which can be constructed by cumulation of a dodecahedron by pyramids of given heights h.

h(r+h)/hresult
-sqrt(1/(10)(5-sqrt(5)))2sqrt(5)-360-faced dimpled deltahedron
1/(19)sqrt(1/5(65+22sqrt(5)))3/(19)(10-sqrt(5))pentakis dodecahedron
sqrt(1/(10)(5-sqrt(5)))2sqrt(5)-360-faced star deltahedron
sqrt(1/5(5+2sqrt(5)))sqrt(5)small stellated dodecahedron

When the dodecahedron with edge length sqrt(10-2sqrt(5)) is oriented with two opposite faces parallel to the xy-plane, the vertices of the top and bottom faces lie at z=+/-(phi+1) and the other polyhedron vertices lie at z=+/-(phi-1), where phi is the golden ratio. The explicit coordinates are

 +/-(2cos(2/5pii),2sin(2/5pii),phi+1)
(1)
 +/-(2phicos(2/5pii),2phisin(2/5pii),phi-1)
(2)

with i=0, 1, ..., 4, where phi is the golden ratio.

Dodecahedron8ProjectionDodecahedron8Dodecahedron8Tilted

Eight dodecahedra can be place in a closed ring, as illustrated above (Kabai 2002, pp. 177-178).

The polyhedron vertices of a dodecahedron can be given in a simple form for a dodecahedron of side length a=sqrt(5)-1 by (0, +/-phi^(-1), +/-phi), (+/-phi, 0, +/-phi^(-1)), (+/-phi^(-1), +/-phi, 0), and (+/-1, +/-1, +/-1).

PentagonApothem

For a dodecahedron of unit edge length a=1, the circumradius R^' and inradius r^' of a pentagonal face are

R^'=1/(10)sqrt(50+10sqrt(5))
(3)
r^'=1/(10)sqrt(25+10sqrt(5)).
(4)

The sagitta x is then given by

 x=R^'-r^'=1/(10)sqrt(125-10sqrt(5)).
(5)

Now consider the following figure.

DodecahedronTrig

Using the Pythagorean theorem on the figure then gives

z_1^2+m^2=(R^'+r^')^2
(6)
z_2^2+(m-x)^2=1
(7)
((z_1+z_2)/2)^2+R^('2)=((z_1-z_2)/2)^2+(m+r^')^2.
(8)

Equation (8) can be written

 z_1z_2+r^2=(m+r^')^2.
(9)

Solving (6), (7), and (9) simultaneously gives

m=r^'=1/(10)sqrt(25+10sqrt(5))
(10)
z_1=2r^'=1/5sqrt(25+10sqrt(5))
(11)
z_2=R^'=1/(10)sqrt(50+10sqrt(5)).
(12)

The inradius of the dodecahedron is then given by

 r=1/2(z_1+z_2),
(13)

so

 r^2=1/(40)(25+11sqrt(5)),
(14)

and solving for r gives

 r=1/(20)sqrt(250+110sqrt(5))=1.11351....
(15)

Now,

 R^2=R^('2)+r^2=3/8(3+sqrt(5)),
(16)

so the circumradius is

 R=1/4(sqrt(15)+sqrt(3))=1.40125....
(17)

The midradius is given by

 rho^2=r^('2)+r^2=1/8(7+3sqrt(5)),
(18)

so

 rho=1/4(3+sqrt(5))=1.30901....
(19)

The dihedral angle is

 alpha=cos^(-1)(-1/5sqrt(5)) approx 116.57 degrees.
(20)

The area of a single face is the area of a pentagon of unit edge length

 A=1/4sqrt(25+10sqrt(5)),
(21)

so the surface area is 12 times this value, namely

 S=3sqrt(25+10sqrt(5)).
(22)

The volume of the dodecahedron can be computed by summing the volume of the 12 constituent pentagonal pyramids,

 V=12(1/3Ar)=1/4(15+7sqrt(5)).
(23)

Apollonius showed that for an icosahedron and a dodecahedron with the same inradius,

 (V_(icosahedron))/(V_(dodecahedron))=(A_(icosahedron))/(A_(dodecahedron)),
(24)

where V is the volume and A the surface area, with the actual ratio being

 (V_(icosahedron))/(V_(dodecahedron))=(A_(icosahedron))/(A_(dodecahedron))=sqrt(3/(10)(5-sqrt(5))).
(25)

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