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While I was reading Ta-Pei Cheng's book on relativity, I was unable to derive the correct relationship between coordinate time $dt$ (the book defined it as the time measured by a clock located at $r=\infty$ from the source of gravity) and proper time $d\tau$ from the definition of metric.

The book states that for a weak and static gravitational field, $g_{00}(r)=-\left(1+\frac{2\Phi(r)}{c^2}\right)$ (with the metric signature $(-1,1,1,1)$ and $\Phi(r)$ is the gravitational potential) and the proper time $d\tau=\sqrt{-g_{00}}\,dt$.

From the gravitational redshift result I know that the above result is correct (in a more unambiguous form $d\tau=\sqrt{-g_{00}(r_\tau)}\,dt$).

However, if I simply use the formula for spacetime interval $ds^2=g_{\mu\nu}dx^\mu dx^\nu$ (assuming two clocks that measure proper time and coordinate time are at rest relative to each other), I have

$$ ds^2=g_{00}(r_\tau)c^2d\tau^2=g_{00}(r_t)c^2dt^2=-c^2dt^2\\ \implies \sqrt{-g_{00}(r_\tau)}\,d\tau=dt$$ This suggests that time flows faster with a lower gravitational potential which is incorrect.

I'm not sure why the above method lead to a wrong conclusion, did I misunderstood the the definition of proper time, coordinate time or spacetime interval?

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Everytime I try and think of time dilation, length contraction or any other strange phenomenon predicted by this strangely beautiful theory I get confused!! Luckily we have a metric to do all the thinking for us. In coordinates $x^\mu=(ct,x,y,z)$ with spacetime signature $(+1,-1,-1,-1)$ the metric is given by \begin{equation} c^2d\tau^2 = ds^2 = c^2dt^2 - d\vec{r}^2 \end{equation} where $d\vec{r}^2=dx^2+dy^2+dz^2$. If the coordinates are parametrised by $\tau$ so that $t=t(\tau), x=x(\tau), y=y(\tau)$ and $z=z(\tau)$ then we may write the above equations as \begin{equation} d\tau = \sqrt{dt^2-d\vec{r}^2} \end{equation} which is equivalent to \begin{equation} d\tau = dt\sqrt{1-v^2} \end{equation} where we adopt a timescale for which $c=1$ and $d\vec{r}/d\tau$ is equvialent to the velocity and hence the relation between coordinate time and proper time between two events at $t_1$ and $t_2$ is \begin{equation} \tau = \int_{t_1}^{t_2}\sqrt{1-v^2}dt \end{equation}

To answer your question, a spacetime interval $ds^2=d\tau^2=-g_{tt}dt^2$, can be expressed as \begin{equation} d\tau=\sqrt{-g_{tt}}dt, \end{equation} by definition. Your definition of the spacetime interval $ds^2$ is slightly off, it should read $ds^2=d\tau^2 = -g_{tt}dt^2+...$

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Hi there, perhaps I have not stated my question clear enough, sorry for that. I want to know why my derivation of the relationship between coordinate time and proper time from the definitions of the metric (not the Minkowski flat metric) and spacetime interval is wrong. – Taptic 3 hours ago
    
Please see above, I've edited my answer. – Rumplestillskin 3 hours ago
    
I'm assuming that in your answer $g_{tt}=g_{00}$. The problem is that given the definition of $g_{00}(r)$, $g_{00}(r_t)=-1$ which is not the desired coefficient. Maybe you could further expand what do you mean by $g_{tt}$ with its explicit expression. Also, I'm not sure what the ellipsis represent in the end, please give a further explanation, thank you! – Taptic 2 hours ago
    
Yep, $g_{tt}=g_{00}$. I alternate between notation to keep myself sane :) Hmmmm I am confused myself now. Why is $g_{00}(r)=g_{00}(r_t)=-1$? In your question you state $ds^2 = g_{00} d\tau^2 = g_{00}dt^2$. This is incorrect. This statement is equating proper time and coordinate time. The line element should read $$ds^2 = d\tau^2 = g_{00}dt^2 - d\vec{r}^2$$ where $c=1$. Do you follow me? – Rumplestillskin 35 mins ago

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