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schematic

simulate this circuit – Schematic created using CircuitLab

Yes, this circuit diagram is correct. No, I did not design it.

How do I describe this circuit in words? I thought about "a switch and light bulb in parallel, instead of series" but the circuit is so bizarre that I want to make sure what I am saying is unambiguous.

I cannot insert a schematic/picture/diagram/drawing, and I have a fairly tight word limit.

If anyone knows the tags for this question, add them.

EDIT (due to interest from the comments): The circuit was made by my 3rd grade teacher for an electricity test (when she thought the questions from the curriculum were too hard for us...)

EDIT 2: No, this is not a fancy NOT gate. The question was "What will happen when the switch closes" and the teacher-accepted answer being "Lightbulb turns on"

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locked by W5VO 7 hours ago

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59  
A fire hazard... – Ignacio Vazquez-Abrams 2 days ago
20  
A danger imminent indicator, with a push-to-make-explosion switch. – Tom Carpenter 2 days ago
13  
Dangerous. | Very dangerous. | Wrong. | Bad. | Stupid. | Actionable. | Job threatening. | ... – Russell McMahon 2 days ago
27  
"Illuminated self-destruct button". – Lundin yesterday
8  
A Samsung Galaxy battery charging circuit? – You'll Delete This As Always yesterday

10 Answers 10

How do I describe this circuit?

Do you want subjective opinion? Or technical description?

Subjective opinion would be: this circuit is badly designed, no matter what problem the designer tried to solve.

Technical description would be: it is a battery killer with stand-by indicator.

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15  
Bahaha "battery killer with a standby indicator" – QPaysTaxes yesterday
    
the exam question to go with that schematic should have been "what do we need to change so that the lamp won't survive either?" – dlatikay 12 hours ago

The best description for this circuit is "How to NOT control a light with a switch." This was clearly not designed by anyone with even basic knowledge of electricity. Or else it was incorrectly "interpreted" or reproduced by someone with absolutely no understanding at all.

Obviously, closing the switch will put a DEAD SHORT across the power supply. That is NEVER a good idea, and can be quite dangerous in many cases.

Clearly, the light bulb (or LED, it makes no difference!) turns OFF when the switch is closed. Anyone who thinks otherwise has zero understanding of electricity and should not be attempting to teach others. In any grade.

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"Battery short circuit stress tester".

This circuit will allow you to observe how the supply source reacts when short circuited. Also tests the switch under extreme fault conditions as well. An expendable person should be deployed to operate the switch.

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16  
+1 for "expendable person" – ppeterka yesterday
    
@ppeterka and the use of 'deployed' – tuskiomi 15 hours ago

Current tends to select line with lower resistance. Short circuit resistance is 0 and open circuit resistance is unlimited. The current of lamp when switch is closed = zero then you have no light but when switch is open the current of lamp is (1.5v/100ohm = 0.015A) then you have light like this picture : enter image description here

and something about the battery :

enter image description here

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sorry for my bad english . – arashzgh 2 days ago
2  
"current Tends to select line with lower resistance" This is not the case. Suppose you have two resistors in parallel, 999 ohm and 1000 ohm. Current will flow in both of them according to ohms law and it will not "select" the 999 ohm one over the 1000 ohm one. – winny 2 days ago
4  
@winny: But more will tend to flow in the 999. Make allowances for translation. – Transistor 2 days ago
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Yes, but that the current would choose the path of least resistance, which is implied here is not true. It will divide itself to minimise the losses. – winny 2 days ago
6  
This answer needs a Youtube link of what happens to the LiPo battery when you press the switch... – Brian Drummond yesterday

I'd describe it as: Switch and bulb in parallel connected to a voltage source.

I think the voltage source should be mentioned (without it you cannot reproduce the circuit, although most would think implicitly that a voltage source is there).

And I don't think a description should contain any hint that this is a quite useless contraption, stuff in school is often not useful or practical but only a test to see if the concepts are understood. An explanation of how it works can contain all the comments on how dangerous and useless this might be. However the solution is wrong - like pointed out by everyone else, if the switch is closed the light will go out.

I've seen something similar while restoring my old Vespa. This answer is more of a try to explain why the teacher might ended up with a wrong circuit.

The generator of a Vespa works like a Dynamo on a bike, so it acts like some sort of current source. And the horn was controlled by a switch which was hooked up in a similar way.

schematic

simulate this circuit – Schematic created using CircuitLab

If you press the button (break the short), the current goes through the horn and you get a nice sound.

In the old schematics, there was no nice current source and the switch was also not depicted like in this schematic but as a normal switch. While analyzing the whole thing I was baffled at first until I drew a complete schematic and measured the switch to realize it's normally closed and pressing it does not close it but open it.

So maybe your teacher came across some circuit like this and in an attempt to make it easier, the circuit was changed in a way to make it wrong and the switch being normally closed was not clear. Most people think of pressing a button or flicking a switch will make a contact.

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I would describe it as a:

"Inverted bulb short ckt w' switch."

Or if you want to describe the circuit construction through words:

"Bulb+switch in parallel"

Though, you could also describe it as:

"Simplest bulb NOT gate."

If you short an alkaline AA 1.5v battery, it's probably not going to heat up as much as you think, especially that it's a small BATTERY which is current limited.

See here.

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No, I think you misunderstood how little my teacher knew (see edit 2 on question) Also, it's a lightbulb, not an LED (there is no lightbulb symbol in the editor). – dpdt 2 days ago
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@dpdt Whoops. Also there is a bulb. Scroll down and you should see a circle with a curved wire or an X inside it. – Bradman175 2 days ago
1  
Thanks! Missed it. – dpdt 2 days ago
    
Having shorted a couple of D cells together before, they certainly get hot enough to give you a burn, although they didn't explode. – The Photon 2 days ago
4  
I use 4 x AA Alkaline batteries in a relatively high powered camera flash for 'events' - allows disposable and fast reload when needed. They supply about the same number of flash cycles as high capacity NimHs in rapid recycle mode. | If used at near maximum recycle rate they come out of the flash so hot that they cannot be handled and probably hot enough to cause burns say 80 C or more. And that's not on short circuit but just heavily loaded. | Shorting a few NimH in a pocket with coins and keys raises them to temperatures that DEMAND immediate depocketisation. Ask me how I know :-). – Russell McMahon 2 days ago

There are only two configurations of a lamp, switch, and voltage source that yield light in one switch state, and no light in the other switch state. So calling this (wrong) one a "light switch" is technically correct.
But the concept of voltage source operation is a rather high level one compared to the concept of a light-switch-circuit, and is likely not the point of the exercise. One could say that the correct series circuit is greener than the energy wasting wrong one. But this is a too-mild tone that doesn't properly convey the danger involved.
I would call it a dangerous light switch.
Another option is to extend the educational experience into the concept of a drained battery and call it a light switch that works once.

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From a circuit theory point of view, this circuit is NOT correct. A closed switch is just a short circuit, and a short circuit is just a special case of voltage source with zero voltage. Therefore, you are imposing two incompatible conditions to the upper node, V=0V and V=1.5V. It is just a logical contradiction, 0=1.5.

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If I were to give it a title, I'd say an illuminated one-switch explosion.

The amount of explosion is based on the current and voltage the power source is meant to provide. For example, using a 9V battery is an opportunity for more explosion in comparison to a 1.5V button battery.

and for **** sakes, PLEASE don't implement this circuit and PLEASE don't make the power source 120 VAC (North american house electricity voltage).

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It's a light circuit with a switch that, when closed, shorts the power source (turning off the light in the process).

It's clearly an incorrect circuit design. Switches are supposed to be wired in series, not in parallel. A dead short will, at a minimum, kill the battery without doing anything useful, and at worst, cause a fire or explosion due to excessive heat.

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