Count text occurrences per line

This one-liner should be able to do what you want:

grep -v ignore input.txt | sed 's/format300/format300\n/g' | grep -c "format300"

basically you are replacing each occurrence of your keyword with the keyword itself and a newline character, which effectively makes your input stream have the keyword only once on any given line. Then grep -c is counting lines with your keyword in them.

You don't need the first cat, that it is known as a Useless use of cat (UUOC).

Also, very useful is grep -o, that only outputs the matching patterns, one per line.

And then, count lines with wc -l.

grep -v ignore YOUR_FILE | grep -o format300 | wc -l

This prints 3 for your small sample.

A Perl way:

perl -lne '$k+=(s/format300//g) unless /ignore/; }{ print $k' input.txt 

The s/format300//g will replace all occurrences of format300 with nothing, and returns the number of replacements. It's a simple way of counting the occurrences. The number is then added to $k and the whole thing only happens if the line doesn't match ignore. The }{ is perl shorthand for "do this after you've finished reading the file, so print $k will print the total number found.

Input file may potentially contain partial matches that would invalidate the result, for example:

1 format300,format250,format300
2 format250,ignore,format160,format300,format300
3 format250,format250,format300
4 format999,format300000,format999
5 format999,ignore_me_not,format300

You don't want to count format300000 on line 4 or ignore line 5 because ignore_me_not contains the substring ignore.

This would do the trick:

grep -v "\bignore\b" FILE |grep -o "\bformat300\b"|wc -l

Correct output is

4

..becase line 2 is ignored, line 5 is not, and line 4 doesn't contain exactly format300.

If you let the wc -l part out, you can see what exactly is being matched: