Running shell command from Python and capturing the output

This is way easier, but only works on Unix (including Cygwin).

import commands
print commands.getstatusoutput('wc -l file')

it returns a tuple with the (return_value, output)

Something like that:

def runProcess(exe):    
    p = subprocess.Popen(exe, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    while(True):
      retcode = p.poll() #returns None while subprocess is running
      line = p.stdout.readline()
      yield line
      if(retcode is not None):
        break

Note, that I'm redirecting stderr to stdout, it might not be exactly what you want, but I want error messages also.

This function yields line by line as they come (normally you'd have to wait for subprocess to finish to get the output as a whole).

For your case the usage would be:

for line in runProcess('mysqladmin create test -uroot -pmysqladmin12'.split()):
    print line,

Vartec's answer doesn't read all lines, so I made a version that did:

def run_command(command):
    p = subprocess.Popen(command,
                         stdout=subprocess.PIPE,
                         stderr=subprocess.STDOUT)
    return iter(p.stdout.readline, b'')

Usage is the same as the accepted answer:

command = 'mysqladmin create test -uroot -pmysqladmin12'.split()
for line in run_command(command):
    print(line)

Your Mileage May Vary, I attempted @senderle's spin on Vartec's solution in Windows on Python 2.6.5, but I was getting errors, and no other solutions worked. My error was: WindowsError: [Error 6] The handle is invalid.

I found that I had to assign PIPE to every handle to get it to return the output I expected - the following worked for me.

import subprocess

def run_command(cmd):
    """given shell command, returns communication tuple of stdout and stderr"""
    return subprocess.Popen(cmd, 
                            stdout=subprocess.PIPE, 
                            stderr=subprocess.PIPE, 
                            stdin=subprocess.PIPE).communicate()

and call like this, ([0] gets the first element of the tuple, stdout):

run_command('tracert 11.1.0.1')[0]

After learning more, I believe I need these pipe arguments because I'm working on a custom system that uses different handles, so I had to directly control all the std's.

To stop console popups (with Windows), do this:

def run_command(cmd):
    """given shell command, returns communication tuple of stdout and stderr"""
    # instantiate a startupinfo obj:
    startupinfo = subprocess.STARTUPINFO()
    # set the use show window flag, might make conditional on being in Windows:
    startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
    # pass as the startupinfo keyword argument:
    return subprocess.Popen(cmd,
                            stdout=subprocess.PIPE, 
                            stderr=subprocess.PIPE, 
                            stdin=subprocess.PIPE, 
                            startupinfo=startupinfo).communicate()

run_command('tracert 11.1.0.1')

Modern Python solution (>= 3.1):

 res = subprocess.check_output(lcmd, stderr=subprocess.STDOUT)

In Python 3.5:

import subprocess

output = subprocess.run("ls -l", shell=True, stdout=subprocess.PIPE, 
                        universal_newlines=True)
print(output.stdout)

I had a slightly different flavor of the same problem with the following requirements:

1. Capture and return STDOUT messages as they accumulate in the STDOUT buffer (i.e. in realtime).
   • @vartec solved this Pythonically with his use of generators and the 'yield'
     keyword above
2. Print all STDOUT lines (even if process exits before STDOUT buffer can be fully read)
3. Don't waste CPU cycles polling the process at high-frequency
4. Check the return code of the subprocess
5. Print STDERR (separate from STDOUT) if we get a non-zero error return code.

I've combined and tweaked previous answers to come up with the following:

def run_command(command):
    p = subprocess.Popen(command,
                         stdout=subprocess.PIPE,
                         stderr=subprocess.PIPE,
                         shell=True)
    # Read stdout from subprocess until the buffer is empty !
    for line in iter(p.stdout.readline, b''):
        if line: # Don't print blank lines
            yield line
    # This ensures the process has completed, AND sets the 'returncode' attr
    while p.poll() is None:                                                                                                                                        
        sleep(.1) #Don't waste CPU-cycles
    # Empty STDERR buffer
    err = p.stderr.read()
    if p.returncode != 0:
       # The run_command() function is responsible for logging STDERR 
       print "Error: " + err                                                                                                                                                                                                                                                                                                                                      

This code would be executed the same as previous answers:

for line in run_command(cmd):
    print line

I had the same problem But figured out a very simple way of doing this follow this

import subprocess
Input = subprocess.getoutput("ls -l")
print(Input)

Hope it helps out

This is a tricky solution that I think it's works in many situations.

import os
os.system('sample_cmd > tmp')
print open('tmp', 'r').read()

A temporary file(here is tmp) is created with the output of command and you can read from it your desired output.

If you need to run a shell command on multiple files, this did the trick for me.

import os
import subprocess

# Define a function for running commands and capturing stdout line by line
# (Modified from Vartec's solution because it wasn't printing all lines)
def runProcess(exe):    
    p = subprocess.Popen(exe, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
    return iter(p.stdout.readline, b'')

# Get all filenames in working directory
for filename in os.listdir('./'):
    # This command will be run on each file
    cmd = 'nm ' + filename

    # Run the command and capture the output line by line.
    for line in runProcess(cmd.split()):
        # Eliminate leading and trailing whitespace
        line.strip()
        # Split the output 
        output = line.split()

        # Filter the output and print relevant lines
        if len(output) > 2:
            if ((output[2] == 'set_program_name')):
                print filename
                print line

Edit: Just saw Max Persson's solution with J.F. Sebastian's suggestion. Went ahead and incorporated that.