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up vote 3 down vote favorite

I would like to plot a 1D graph with two curves that identically overlap. For example, trivially consider 

Plot[Sin[x], {x, 0, 3}]

What are the best options to use to plot two overlapping $\sin$ cuves (in the same domain) such that the graphs are (to some extent) visually distinguishable so that the reader can say -- yes, these two plots are the same (for more interesting cases, though).

Thanks.

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3  
Why not plot the difference of the two functions? – march 8 hours ago
up vote 5 down vote

For any curves that might overlap even just a little:

Plot[{Sin[x], Sin[x]}, {x, 0, 3}, 
 PlotStyle -> {{Thickness[0.03], LightGray}, Red},
 PlotLegends -> {"Curve 1", "Curve 2"}]

Two identical curves

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up vote 4 down vote

Use a combination of Show with MeshStyle and/or PlotStyle

Show[
 Plot[Sin[x], {x, 0, Pi}, Mesh -> 20, 
  MeshStyle -> Directive[PointSize[0.02], Red], 
  PlotStyle -> Directive[Thickness[0.01], Red], MaxRecursion -> 0],
 Plot[Cos[x - Pi/2], {x, 0, Pi}, Mesh -> 20, 
  MeshStyle -> Directive[PointSize[0.01], Blue], 
  PlotStyle -> Directive[Thickness[0.0025], Blue], MaxRecursion -> 0]
 ]

enter image description here

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兄弟reputation涨得好猛 :) – yode 42 secs ago
up vote 4 down vote

Using Epilog directly.

Plot[Sin[x], {x, 0, 3}, 
     PlotStyle -> {Blue, Opacity[0.5]}, 
     Epilog -> {Dashed, Red, Line[Table[{t, Sin[t]}, {t, 0, 3, 0.1}]]}]

enter image description here

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