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3

Many of you may have interacted with people from Russia on the internet at some point, and a subset of you may have noticed the slightly odd method they have of expressing themselves.

e.g. деинсталляция игра нуб))) - (forgive the google translate)

where the ))) are added for emphasis on the previous statement, I have been working on a theory that the ratio of )'s to the rest of the string is directly proportional to the amount of implied emphasis, however I oftentimes find it difficult to compute the ratio on the fly, as I am also trying to cope with a slew of abuse, so I would like the shortest possible code to help me calculate what the resulting string should be, for a value of enthusiasm between 0 and 500%, given the original, unenthusiastic string, this will aid my research greatly as i will not have to type out bulky scripts every time I wish to test my hypothesis.

so, the challenge:

write a full program or function, which, provided two arguments, a string of unknown length, and a number, in either integer format (between 0 and 500) or in decimal format (between 0 and 5, with 2 points of accuracy) will

  • return/display the original string, suffixed with a number of )'s
  • the number will be the calculated as a ratio of the input number to the string length.
  • so if the number 200, or 2.00 was provided, 200% of the string must be suffixed as )'s
  • the number of brackets rounded to in decimal situations does not matter.
  • script is required to support Printable ASCII characters.
  • only has to support one input number format, of your choice.

examples:

"codegolf" 125      = codegolf))))))))))
"codegolf" 75       = codegolf))))))
"noob team omg" 0.5 = noob team omg))))))
"hi!" 4.99          = hi!)))))))))))))))

example code (powershell) (with decimal input):

Function Get-RussianString ([string]$InputStr,[decimal]$Ratio){
    $StrLen = $InputStr.Length
    $SuffixCount = $StrLen * $Ratio
    $Suffix = [string]::New(")",$SuffixCount)
    return $InputStr + $Suffix
}

Get-RussianString "codegolf" 0.5
codegolf))))

this is so shortest code wins!

share|improve this question
15  
You were picking up those Russians on a dating site, weren't you? – Dmitry Grigoryev 16 hours ago
15  
@DmitryGrigoryev the banner ad told me they were beautiful and looking for love. – ConnorLSW 15 hours ago
2  
I wonder if it makes up for all the unmatched ('s in TI-BASIC... – 12Me21 14 hours ago
7  
@CaptainMan No ) is reduced emoticon :). It is used very common between young people as far as I know. – talex 14 hours ago
1  
) is not an emphasis, it is simply the smiley. As far as I know, it is harder to type : when using Russian keyboard layout, therefore they smile without eyes. – Juris 14 hours ago

19 Answers 19

up vote 6 down vote

Perl 6, 21 bytes

{$^a~")"x$^b*$a.comb}
share|improve this answer
up vote 5 down vote

Jelly, 7 bytes

ȮL×Ċ”)x

Try it online!

Uses the decimal format.

How?

ȮL×Ċ”)x - Main link: string, decimal
Ȯ       - print string
 L      - length(string)
  ×     - multiply by the decimal
   Ċ    - ceiling (since rounding method is flexible)
    ”)  - a ')' character
      x - repeated that many times
        - implicit print
share|improve this answer
    
@ConnorLSW I just noticed that this will print the required string as a full program, but that the specification states "return" - is this OK? – Jonathan Allan 16 hours ago
1  
any standard accepted output format is fine – ConnorLSW 14 hours ago
    
Thanks, I just thought it best to double check. – Jonathan Allan 14 hours ago
    
no worries - this is my first challenge so there's a few of these things that I missed, i've updated it in the question to be more clear - thanks for asking. – ConnorLSW 14 hours ago
up vote 4 down vote

PowerShell, 33 bytes

$a,$b=$args;$a+')'*($b*$a.Length)

Try it online!

Supports decimal format.

share|improve this answer
up vote 3 down vote

05AB1E, 9 8 bytes

g*ï')×¹ì

Try it online!

g*       # Length, multiplied by emphasis.
  ï')×   # Covnerted to an integer, push that many parenthesis.
      ¹ì # Prepend original string.

Works for both integer and decimal, arguments order: f(String, Double)

share|improve this answer
up vote 3 down vote

JavaScript ES6, 38 31 30 bytes

s=>n=>s+')'.repeat(s.length*n)


f=s=>n=>s+')'.repeat(s.length*n)

console.log(f("hi!")(4.99))

share|improve this answer
1  
Nice, I think that's the shortest possible. You can save a byte through currying: s=>n=>s+')'.repeat(s.length*n) (it would then be called like f("hi!")(4.99)) – ETHproductions 16 hours ago
up vote 2 down vote

Python, 30 bytes

lambda s,r:s+')'*int(len(s)*r)

Uses the decimal input.

Try it online!

share|improve this answer
up vote 2 down vote

R, 62 46 bytes

Anonymous function that takes string s and decimal n, prints output to stdout.

function(s,n)cat(s,rep(")",n*nchar(s)),sep="")
share|improve this answer
up vote 1 down vote

CJam, 9 bytes

l_,ld*')*

Try it online!

Input string on the first line, emphasis ratio in range 0 to 5 on the second.

Explanation

l    e# Read input string.
_,   e# Duplicate, get length.
ld   e# Read emphasis ratio.
*    e# Multiply by length.
')*  e# Get that many parentheses.
share|improve this answer
up vote 1 down vote

Python 2, 29 bytes

lambda s,p:s+len(s)*p/100*')'

s in the string, p is the percentage (integer).

Try it online!

share|improve this answer
up vote 0 down vote

SmileBASIC, 29 bytes

INPUT S$,N?S$;")"*(LEN(S$)*N)
share|improve this answer
    
since 3*4.99 = 14.97, only 14 or 15 would be acceptable as answers, the 29 bytes version should work fine though, sorry! – ConnorLSW 15 hours ago
up vote 0 down vote

Pyth, 9 bytes

*s*lpzE")

Takes two lines of input: string and ratio (decimal).

Try it on pyth.herokuapp.com

Explanation

A denotes a function's first argument, B its second argument.

*s*lpzE")
    pz     # print the input string
   lAA     # take the length of the printed string
      E    # read the next line of input (the emphasis ratio)
  *AAAB    # multiply the length by the ratio
 sAAAAA    # floor the result
*AAAAAA")  # repeat ")" n times
           # implicit print
share|improve this answer
up vote 0 down vote

C#, 77 bytes

string r(string s,int p)=>s+new string(')',(int)Math.Round(s.Length*p/100d));

C# interactive is sweet.

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up vote 0 down vote

Gol><> (Golfish), 17 bytes

i:a=?v
R*Il~/Hr)`

Try it here.

The top line reads characters (i) until it finds a newline (ASCII 10, a), then goes down (v).

Then we discard one character (the newline) with ~, push the length of the stack (l), read a float (I), multiply the two, and repeatedly (R) push the character ")" that many times. Finally, reverse the stack (r), output it and halt (H).

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up vote 0 down vote

MATL, 11 10 8 bytes

yn*:"41h

This solution uses the decimal form of the second input

Try it online!

Explanation

        % Implicitly grab first input as a string
        % Implicitly grab the second input as a number
y       % Make a copy of the first input
n       % Compute the length of the string
*       % Multiply the decimal by the length to determine the # of )'s (N)
:       % Create the array [1...N]
"       % For each element in this array
  41    % Push 41 to the stack (ACSII for ")")
  h     % Horizontally concatenate this with the current string
        % Implicit end of for loop and display
share|improve this answer
up vote 0 down vote

TI-Basic, 33 bytes

Takes decimal input.

Prompt Str1,A
")
For(I,0,9
Ans+Ans
End
Str1+sub(Ans,1,AI
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up vote 0 down vote

Bash + coreutils, 45 bytes

echo $1`seq -s\) $[${#1}*$2/100+1]|tr -cd \)`

Try it online!

Integer input.

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up vote 0 down vote

Perl 5, 31 bytes

sub f{($_=pop).')'x(y///c*pop)}

(Number is first arg, string is second.)

Try it online!

share|improve this answer
up vote 0 down vote

sB~, 17 bytes

i\,N?\;')'*(N*l(\

Explained:

i\,N    input a string and a number
?\;     print the string
')'*    also print ) multiplied by...
(N*l(\  the number times the string length.

Parentheses are closed automatically

Here's the output of the compiler, if you're interested:

 INPUT  S$ ,N? S$ ;")"*(N* LEN(  S$ ))

This version of the compiler was written on 1/27/2017 at 11:12 pm, which might have been a few minutes after this question was posted. So here's a version which works on the oldest version of the compiler, written an hour earlier: iS$,N?S$;')'*(N*l(S$)) (22 bytes)

share|improve this answer
up vote 0 down vote

PHP, 50 bytes

<?=str_pad($s=$argv[1],strlen($s)*++$argv[2],")");

takes string and decimal number as command line arguments; cuts padding. Run with -r;

breakdown

<?=                     // print ...
str_pad(                    // pad
    $s=$argv[1],            // string=argument 1
    strlen($s)*++$argv[2],  // to string length*(1+argument 2) 
    ")"                     // using ")" as padding string
);
share|improve this answer

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