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This might be a very simple challenge, but I am surprised it hasn't been done on code-golf yet:

Print all Integers from 1 to 10 inclusive in ascending order to the Standard Output

Your output format can be whatever your language supports. This includes arbitrary separators (commas, semicolons, newlines, combinations of those, ...), prefixes and postfixes (like [...]).

This is , so shortest answer in bytes wins!

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3  
Related (duplicate?) – Luis Mendo yesterday
9  
If the only change is hard-coding a single parameter then that falls under the banner of "trivial change", and by the standards of this site still counts as a dupe. – Peter Taylor yesterday
7  
@PeterTaylor The other challenge has a huge problem with the integer limits though. The way it's specified every TC language that doesn't have 64-bit integers needs to implement them. (And that affects quite a lot of languages.) – Martin Ender yesterday
5  
@MartinEnder It's too bad the other question has the silly limitation, but I still think it's a dupe when one can port over 2/3 or more of the answers with only minor modification. – xnor yesterday
8  
@xnor Quite frankly, I'd rather close the other challenge as a duplicate of this one. The requirement pretty much ruins it. – Dennis yesterday

75 Answers 75

C, 36 bytes

main(i){while(printf("%d ",i++)<3);}

This works because the loop terminates after the first 2 digit number.

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1  
There's no mention of being able to pass in parameters to the function. – Ash Burlaczenko yesterday
1  
@AshBurlaczenko What are you talking about? This is a standard technique in golfing to initialise an int to 1. You don't need to pass any command line arguments. In fact, doing so will cause the program to produce the wrong output. – xsot yesterday
3  
@AshBurlaczenko By consensus we have agreed that programs may assume they will not be called with unnecessary input (in this case, no additional command line arguments, beyond the program itself). That means i here will always be 1 when this program is run. Did you mean something else? – FryAmTheEggman yesterday
1  
Sorry, I've not written C but assumed it's default value would be 0 as in every language I've used. – Ash Burlaczenko yesterday
8  
@AshBurlaczenko In C, the first argument to main is the number of command line arguments (including the executable name itself). Since no additional arguments are passed, that count is 1. The second argument to main is the actual list of command line arguments, but that argument is ignored in this program. – Chris Bouchard yesterday

Bash, 12 characters

echo {1..10}

Sample run:

bash-4.3$ echo {1..10}
1 2 3 4 5 6 7 8 9 10

Bash + coreutils, 10 characters

(Just trying to be funny and using ': No such file or directory↵ls: cannot access ' as separator.)

ls {1..10}

Sample run:

bash-4.3$ ls {1..10}
ls: cannot access '1': No such file or directory
ls: cannot access '2': No such file or directory
ls: cannot access '3': No such file or directory
ls: cannot access '4': No such file or directory
ls: cannot access '5': No such file or directory
ls: cannot access '6': No such file or directory
ls: cannot access '7': No such file or directory
ls: cannot access '8': No such file or directory
ls: cannot access '9': No such file or directory
ls: cannot access '10': No such file or directory

Bash + coreutils, 6 characters

(Just trying to be boring. Or not just trying…)

seq 10

Sample run:

bash-4.3$ seq 10
1
2
3
4
5
6
7
8
9
10
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2  
Last one is just seq/coreutils, bash not involved. – hyde 23 hours ago

Jelly, 2 bytes

⁵R

Explanation

⁵  Return the fifth command line argument or 10
 R Range
   Implicit output
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2  
⁵R, two bytes – Luis Mendo yesterday

05AB1E, 2 bytes

Code:

TL

Explanation:

T   # Constant for 10
 L  # Range

Try it online!.

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Brainfuck, 58 bytes

-[----->+>+<<]>--<+++++[<++<++>>-]<<-[->>>.+<<.<]>>>>--.-.

Try it online!

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1  
Beat me to it, and shorter too, will post mine anyway as I don't think we've used the same trick. Have my +1 :) – Katenkyo yesterday
    
@LuisMendo Fixed. – Loovjo yesterday

Pyth, 2 bytes

ST

First time I've used a golfing lang to answer!

Explanation:

S    1-indexed range. [1, 2, ... A].
 T   Variable. Initialized to 10. (Ten)
     Implicitly printed.
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Ninja'd by seconds :/ – TùxCräftîñg yesterday

CJam, 6 5 bytes

A,:)`

1 byte saved thanks to Luis Mendo

Output: [1 2 3 4 5 6 7 8 9 10]

Explaination:

A,      e# Push a list from 0 to 9.
  :)    e# Increment all values.
    `   e# Stringify the list.

Try it online!

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i like the smileyface. (Isn't there an error in your explanation: A, creates a list from 0 to 9) – KarlKastor yesterday
    
@KarlKastor Thanks, fixed. – Loovjo yesterday

MATL, 3 bytes

10:

Try it online!

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Actually, 9 Bytes

19`;1+`na

Try it here!

Explanation:

19`;1+`na

1           Push 1 to stack
 9          Push 9 to stack
  `;1+`     Push Function inside ` to stack
   ;        Push top element to stack
    1+      Add 1 to top element
       n    Run function x times (9 times)
        a   Invert stack
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6  
Welcome to Programming Puzzles and Code Golf! – Adnan yesterday

Ruby, 8 bytes

Seperated by newlines.

p *1..10
share|improve this answer
    
*Separated by newlines. – David Conrad 43 mins ago

Perl 6, 12 bytes

say @(1..10)

The @() is needed to convert to an array

Alternative solution:

say @(^10+1)

Builds a range 0..10, then adds one, then converts to an array.

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For Perl 5.10, 14 bytes and almost like yours: say for(1..10) – Paul Picard yesterday
    
@PaulPicard do post it! Perl 5 is a different language. – ven yesterday

Mathematica - 13 bytes

Echo@Range@10

Saved 4 bytes thanks to MartinEnder!

Output: >> {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

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Java 7, 53 51 52 bytes (loop)

void l(){for(int i=0;++i<11;)System.out.println(i);}

Alternative 51 bytes (hardcoded is shorter.., but considered a default loophole, so not allowed):

void h(){System.out.print("1 2 3 4 5 6 7 8 9 10");}

Alternative 54 bytes (recursive):

int i=1;void r(){System.out.println(i);if(i++<10)r();}

Ungolfed & test code for all three:

Try it here.

class Main{
  static void h(){
    System.out.print("1 2 3 4 5 6 7 8 9 10");
  }      

  static void l(){
    for(int i=0; ++i < 11;){
      System.out.println(i);
    }
  }

  static int i = 1;
  static void r(){
    System.out.println(i);
    if(i++ < 10){
      r();
    }
  }

  public static void main(String[] a){
    h();
    System.out.println();
    l();
    System.out.println();
    r();
  }
}
share|improve this answer
    
Loop can be for(int i=1;i<11;)System.out.println(i++), saves one byte. – Clashsoft yesterday
    
Hardcoding the output is a standard loophole. – zyabin101 yesterday
    
@zyabin101 Changed the order so the hard-coded answer is non-competing. Still left it in the answer though, since it's pretty funny (and sad) that hard-coded is the shortest way to print 1-10 in Java 7.. – Kevin Cruijssen yesterday

R, 4 characters

 1:10

The ":" is probably one of the most used R commands.

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Should they require printing a string, not returning a vector, consider cat(1:10). – Andreï Kostyrka 1 hour ago

Fuzzy Octo Guacamole, 7 bytes

1.25*$:

Multiplies 2*5, takes the range of that and 1, and prints the whole stack.

1.25*$:
1.      # Push 1 to the stack and switch stacks
  25*   # Push 10 to the stack
     $  # Push every number in the inclusive range on the top of inactive stack and top of active stack ([1,2,3,4,5,6,7,8,9,10])
      : # Print the stack, which is a list containing the numbers.
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><>, 13 bytes

01+:a)?;:nao!

Explanation :

01+:a)?;:nao!

0                 push initial value of n on the stack
 1+               increments n
   :              duplicates n on the stack
    a             push 10 on the stack
     )            pops n and 10 of the stack, push n>10 on the stack
      ?;          if n>10, stops program execution
        :n        duplicates n on the stack in order to display it
          ao      display 10 (x0A, linefeed)
            !     skips the next instruction, which since ><> loops is the push 0

You can see it in action on the online interpreter.

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Could you please add an explanation? – Clashsoft yesterday

Python - 19 17 bytes

print range(1,11)

Saved 1 byte, thanks to KevinLau - not Kenny!

Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

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Use range instead of xrange, assuming Python 2. In fact, this current version doesn't seem to work on my machine in either Python version. – Kevin Lau - not Kenny yesterday
    
@KevinLau-notKenny I could've sworn that I tried that, and got nothing to STDOUT. Thanks! – TuukkaX yesterday

Groovy, 11 characters

print 1..10

Sample run:

bash-4.3$ groovy -e 'print 1..10'
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
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Haskell, 17 bytes

main=print[1..10]

Outputs [1,2,3,4,5,6,7,8,9,10].

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I'm a bit confused here... I'm almost certain that it should be [1..10]. I don't have access to a haskell compiler, but I'll double-check in the morning. – Zwei yesterday
    
@Zwei Ranges don't include their upper limit in Haskell. – C. Quilley yesterday
    
@C.Quilley They totally do. You might be thinking of Python. – xnor yesterday
    
Huh, I was sure I had tested this code. Apologies for the earlier assertion. – C. Quilley yesterday

PowerShell, 5 bytes

1..10

Creates a dynamic range with the .. operator from 1 to 10, then that array is left on the pipeline. Output is implicit. Default .ToString() method of an array is newline, so this will be newline-separated when run in a clean shell.

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Sesos (binary), 5 bytes

Hexdump:

0000000: 2c4bbc 3301                                       ,K.3.

Try it online!

How it works

The binary file above has been generated by assembling the following SASM code.

Sesos is a language "based on brainfuck", but is "concise, can be typed easily, has somewhat flexible I/O, and is safe for work".

set numout    ;sets the output to printing a number per line,
              ;instead of characters.
add 10        ;now the tape is [10,0,...]
jmp           ;start of loop
              ;sets an entry marker and jump to the jnz instruction.
    fwd 1          ;forward the data head 
    add 1          ;add 1 to the cell under data head
    put            ;output (as number)
    rwd 1          ;rewind the data head by 1 cellby 1 cell
    sub 1          ;subtract 1 from the cell under data head
                   ;the tape goes from [0,10] to [1,9], to [2,8]
                   ;to ... [8,2] to [9,1] to [10,0] and then halts.
              ;(implicit jnz) end of loop, goto "jmp" if not zero

In brainfuck: ++++++++++[>+.<-] (assuming decimal output).

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LOLCODE, 79 bytes

IM IN YR l UPPIN YR v TIL BOTH SAEM v AN 10
VISIBLE SUM OF v AN 1
IM OUTTA YR l

This code may need some tweaking depending on the compiler you're using. Some want you to add HAI/KTHXBYE, some want you to declare the variable ahead of time. One compiler breaks if your loop name is shorter than two characters, even though the loop name is never used.

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Lua, 25 Bytes

for i=1,10 do print(i)end
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Retina, 13 bytes

I've got two solutions at this byte count, but it doesn't seem optimal:


_10$*
1
$.`_

11$*_
\B
$.`

They both use _ as separators, prefix and suffix.

Try the first online! Or try the other one!

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Brachylog, 6 5 bytes

Saved one byte thanks to @mat

10yb.

Try it online!

Explanation

10y        Get the list [0:1:2:3:4:5:6:7:8:9:10]
   b.      Output is that list minus the first element
share|improve this answer
    
5 bytes: 10yb. – mat yesterday
    
@mat Thanks, I didn't thought of that, even though it's even simpler! – Fatalize yesterday

Racket, 12 bytes

(range 1 11)

Prints '(1 2 3 4 5 6 7 8 9 10).

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Julia 0.2, 11 bytes

print(1:10)

Pretty self explanatory. 1:10 is a range, and print expands it.

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Dyvil, 22 bytes

for(x<-1..10)println x

23 bytes

for x<-1..10{println x}

Two ways to do the same thing: for-each loop over the range 1..10 with type-inferred loop variable x. The loop body calls the built-in println(int) function with the argument x.


24 bytes

println{for x<-1..10{x}}

This version calls the built-in println(AutoPrinter.()->void) method. An AutoPrinter instance is implicitly available to the {for ...} block, which is passed as an anonymous function. The AutoPrinter class has an applyStatement(any) method, which is called when an expression like x appears in a statement context. The implementation forwards to println(any), which prints the expression.


26 bytes

(1..10).forEach(println _)

Functional approach; creates an IntRange object and calls its forEach(int -> void) (higher order) method. The argument is an anonymous lambda function that passes the argument to the aforementioned println(int) method. In this case, println _ is syntactic sugar for the lambda expression x => println x. Again, the types are inferred by the compiler, so that it internally becomes (int x) => println x.


Output in all cases:

1
2
3
4
5
6
7
8
9
10
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J, 6 bytes

1+i.10

Output: 1 2 3 4 5 6 7 8 9 10

Explaination:

1+       NB. Add one to...
  i.10   NB. A range from 0 to 9.
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